<!DOCTYPE html>
<html>
<head>
	<title>查询QQ信息</title>
	<style type="text/css">
		table {
			border-collapse: collapse;
			width: 50%;
			margin: auto;
			font-family: Arial, Helvetica, sans-serif;
			font-size: 14px;
		}
		th, td {
			padding: 8px;
			text-align: left;
			border-bottom: 1px solid #ddd;
		}
		th {
			background-color: #4CAF50;
			color: white;
		}
		tr:hover {
			background-color: #f5f5f5;
		}
	</style>
</head>
<body>
	<h1>查询QQ信息</h1>
	<form action="" method="GET">
		<label for="qq">QQ号码:</label>
		<input type="text" name="qq" id="qq" required>
		<button type="submit">查询</button>
	</form>
	<?php
		if(isset($_GET['qq'])) {
			$qq = $_GET['qq'];
			$url = "https://v.api.aa1.cn/api/api-qq-gj/index.php?qq=$qq";
			$data = file_get_contents($url);
			$result = json_decode($data, true);
			if($result['code'] == 1) {
				echo "<table>";
				echo "<tr><th>QQ号码</th><td>{$result['qq']}</td></tr>";
				echo "<tr><th>价格</th><td>{$result['money']}</td></tr>";
				echo "<tr><th>等级</th><td>{$result['dengji']}</td></tr>";
				if($result['vip'] == 1) {
					echo "<tr><th>VIP会员</th><td>否</td></tr>";
				} else {
					echo "<tr><th>VIP会员</th><td>是</td></tr>";
				}
				echo "</table>";
			} else {
				echo "<p>查询失败,请重新输入QQ号码</p>";
			}
		}
	?>
</body>
</html>
用php写成查询代码 需要有样式接口地址:httpsvapiaa1cnapiapi-qq-gjindexphp返回格式:JSON请求方式:GET 暂无层级展示仅供参考 code 1:返回正常0:返回错误 qq qq号码 money qq价格 dengji qq等级 vip 1:非会员2:会员

原文地址: http://www.cveoy.top/t/topic/M3F 著作权归作者所有。请勿转载和采集!

免费AI点我,无需注册和登录